We will work on the same examples to verify our implementations and fill up the following tables for comparisons when we proceed:
SigmaYY | Elapsed Time | Iterative Steps | |
T4 | |||
T10 | |||
TP2 | |||
REF | 1.0 |
KI (x=0.5) | Elapsed Time | Iterative Steps | |
T4 | |||
T10 | |||
TP2 | |||
REF | 5.23 (Single Edge Notch, 2D FRANC2D) |
---|
Perform the same procedures for CubeCrack_T4.
cp CubeCrack.geo CubeCrack_T4.geo
cp CubeCrack.msh CubeCrack_T4.msh
....
Also, in franc3d do:
"Visualize/Analyze Results", "Fracture Analysis", "Stress Intensity
Factor", accept defaults. It should show three plots with the stress
intensity factors along the crack front. Write down KI value at x=0.5.
Now, do you see a uniform stress distribution for the cube? Do you think the T4 element is adequate to approximate the unknown displacement and stress fields for this problem? Why?
Now, what do you think? Does the quadratic shape function (T10) give you a better approximation of the solutions than the linear shape function (T4)? Does it take longer computational time and/or iterative steps to solve the problems?
Statistical Mechanics: Entropy, Order Parameters, and Complexity,
now available at
Oxford University Press
(USA,
Europe).